Type of callcc: Revision history

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7 October 2020

  • curprev 08:2208:22, 7 October 2020‎ Mike talk contribs‎ 1,059 bytes +1,059‎ Created page with "{{Proglan}} The monad of continuations defines :@@M 'a = ('a -> Answer) -> Answer@@ and with this definition of @@M@@, I said that @@callcc@@ has type :@@callcc :: (('a -> M '..."
Retrieved from "https://spivey.oriel.ox.ac.uk/proglan-x/Type_of_callcc"